Passing 2D array to function using pointer

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Hi
I am getting and error while passing 2d array to function.
It gives me following error
error C2664: cannot convert parameter 1 from int [3][4] to int*
I am not able to figure out where i am making mistake. Here is my code

C#

#include<iostream>
#include<conio.h>

using namespace std;

class Demo
{
public:
	void TwoDArrPass1(int *arr,int col,int row)
	{
	}

};

void main()
{
	Demo dd;
	int Arr[3][4] =	{	{1,2,3,4},
						{10,20,30,40},
						{100,200,300,400}
					};
	dd.TwoDArrPass1(Arr,3,4);

	_getch();
}

What I have tried:

I have tried to search but not getting any clear idea about my mistake.
Thanks in advance for help

Posted 15-Jun-16 0:58am

sanx84

Updated 15-Jun-16 1:48am

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Member 14507089 8-Jul-19 8:26am

please ans it

2 solutions

Solution 1

This has been asked multiple times and can be answered therefore by searching the web.

So I have done this for you instead of repeating something said already:
Passing a 2D array to a C++ function - Stack Overflow[^]
Passing 2d array to pointer in C++ - C++ Forum[^]
Pointer to Pointer and Reference to Pointer[^]
How to Pass a Two Dimensional Array to a Function (C++)[^]

Posted 15-Jun-16 1:34am

Jochen Arndt

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CPallini · Accepted Answer · 2016-06-15T01:41:00

A cast would do the trick, e.g.

C++

 #include<iostream>

 using namespace std;

class Demo
{
public:
  void TwoDArrPass1(int * arr ,int col,int row)
  {
    for ( int c = 0; c<col; ++c)
    {
      for (int r=0; r<row; ++r)
      {
        cout << arr[row*c+r] << " ";
      }
      cout << endl;
    }
  }

};

int main()
{
  Demo dd;
  int Arr[3][4] = { {1,2,3,4},
            {10,20,30,40},
            {100,200,300,400}
          };
  dd.TwoDArrPass1(reinterpret_cast<int *>(Arr),3,4);
}