How can I replace an item with an item?

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Hi So at the moment, i have a max of 4 items showing.

When user clicks a button, i want that item to be replaced with another item?

I have tried extending the count which does work but is there any way i can actually replace that selected one with that item?

see code below.

What I have tried:

$cnt=0;
$max=4;


$Displayed=false;
$inserted=false;


while($dbRow=$dbQuery->fetch(PDO::FETCH_ASSOC) and ($cnt < $max))  
 {		
   echo "".$dbRow["Name"]."</h4><br>"."<br><img src=/".$dbRow['Picture']."'width='150' height='150' />"."<br><br>".$dbRow["Instructions"]."
			

<form method='POST'><input type='hidden' name='MealID' value= '".$dbRow['MealID']."'>
<input type='submit' name='submit' value='Complete'></form>";
	
			
$cnt++;
if(($_POST['MealID'])) {
	$max=5;
}

Posted 4-Apr-18 22:40pm

Member 13637584

Updated 5-Apr-18 5:14am

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W∴ Balboos, *GHB* · Answer 1 · 2018-04-05T05:15:00

Best way to replace things on a web page is AJAX[^]

All of your items must have an id='' to be targeted by AJAX

You don't use a form - you send the data to the server and it sends data back to the page - which then updates the targeted item.

AJAX is invoked in a javaScript - but the link I supplied will give you a boiler-plate level example and you only need to change it to match your page's data and control ID's. The PHP on the server side does work - returns data - but doesn't replace your page as would a <form> - for most things, this is far superior to forms for changing data viewed by the user.