bind image button id to window.open method

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hello sir.

I have two pages. a.aspx, b.aspx. There are 4 buttons in a.aspx, when we click button1 or button2 or button3 or button4 new window should be opened. and there is some different functionality for each button.
my doubt is how bind each button to window.open method.

If any body know please help me.

My code is below:

a.aspx
------

XML

<script type="text/javascript">
        function openwindow() {
            window.open("AllPageDetails.aspx", "mywindow", "menubar=1,resizable=1,width=350,height=250");
        }

    </script>

XML

<asp:ImageButton ID="ImgBtnCategory" runat="server" OnClientClick="openwindow()" PostBackUrl ="~/AllPageDetails.aspx?ImgBtnCategory=Category"/>

b.aspx
------

C#

if (Request.QueryString["ImgBtnCategory"] == "one")
            {
                LblId.Text = "Actor Id";
                LblName.Text = "Actor Name";
                TxtExtra.Visible = false;
            }

Posted 9-Nov-10 2:16am

sathish.jampala

Updated 9-Nov-10 3:30am

Henry Minute

v2

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Henry Minute 9-Nov-10 9:31am

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Ed Guzman · Accepted Answer · 2010-11-09T05:56:00

I would disable the postbackurl:

PostBackUrl ="JavaScript.Void(1);"

then change javascript function:

XML

<script type="text/javascript">
       function openwindow(id) {
       window.open("AllPageDetails.aspx?id=" + id, "mywindow", "menubar=1,resizable=1,width=350,height=250");
        }
    </script>

And pass this id from your OnClientClick:

C#

OnClientClick="openwindow(1);"

After that you will handle this is on the server side to display the proper result.