CRecordView & CDialog::DoModal()

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I have created an application with ODBC support & created a CRecordView class associated with a Crecordset class & Form View. The problem is that I am stuck to just Show that CRecordView derived class like CDialog::DoModal() function do.
Help me please to make this possible :((, & I will be grateful for a convincing answer.

Posted 25-Dec-10 1:23am

Mr. Tomay

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#realJSOP 25-Dec-10 7:50am

What exactly are you asking?

3 solutions

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Mr. Tomay · Answer 1 · 2010-12-27T00:18:00

Solution 1

I am asking for method to show a CRecordView derived class like showing a CDialog derived class with DoModal() function.

Posted 27-Dec-10 0:18am

Mr. Tomay

Richard MacCutchan · Answer 2 · 2010-12-27T01:40:00

Solution 2

I'm not sure what your question is really asking, but you may find the answer here[^].

Posted 27-Dec-10 1:40am

Richard MacCutchan

Mr. Tomay · Answer 3 · 2010-12-27T08:22:00

Solution 3

Well,
The question is: How to implement
CWnd* CFrameWnd::CreateView(CCreateContext* pContext, UINT nID = AFX_IDW_PANE_FIRST); function, & then show it as modal ?

NB: My view class is CRecordView derived class.

Sorry for my bad english :(

Posted 27-Dec-10 8:22am

Mr. Tomay

Updated 27-Dec-10 8:23am

v2

Comments

Richard MacCutchan 27-Dec-10 15:18pm

You cannot use DoModal() on a view only on a dialog. Take a look at the link I gave you, there is information there to help you show CRecordView data.

Mr. Tomay 28-Dec-10 10:30am

I heard about a trick of creating a CFrameWnd instance and call the function CFrameWnd::CreateView(); to create the CRecordView view, & then create a new CDialog instance, then set the parent windows of the newly created CRecordView to the newly created CDialog window, & finally show it calling CDialog::DoModal() function. But I don't know how to do it :Confused: