xslt code for change the menu lable just click on it

<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl">
    <xsl:output method="xml" indent="yes" encoding="utf-8"/>
    <!-- Find the root node called Menus
      and call MenuListing for its children -->
    <xsl:template match="/Menus">
        <MenuItems>
            <xsl:call-template name="MenuListing" />
        </MenuItems>
      <xsl:for-each select="Menus">
        <xsl:choose>
          <xsl:when test="Name!=''">
            <xsl:text>HomePage</xsl:text>
          </xsl:when>
          <xsl:otherwise>
            <xsl:text>HomePage</xsl:text>
          </xsl:otherwise>
        </xsl:choose>
      </xsl:for-each>

    </xsl:template>
    <!-- Allow for recusive child node processing -->
    <xsl:template name="MenuListing">
        <xsl:apply-templates select="Menu" />
    </xsl:template>
    <xsl:template match="Menu">
 <MenuItem>
            <!-- Convert Menu child elements to MenuItem attributes -->
            <xsl:attribute name="MenuText">
                <xsl:value-of select="Name"/>
            </xsl:attribute>
   <xsl:attribute name="tooltip">
                <xsl:value-of select="ToolTip"/>
            </xsl:attribute>
   <xsl:attribute name="destUrl">
     <xsl:value-of select="NavigateUrl"/>
   </xsl:attribute>
            <!-- Call MenuListing if there are child Menu nodes -->
            <xsl:if test="count(Menu) > 0">
                <xsl:call-template name="MenuListing" />
            </xsl:if>
        </MenuItem>
      <!--</xsl:for-each>-->
    </xsl:template>
</xsl:stylesheet>