Always Visible Control Extender

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I have populated certain rows in gridview control through code behind. Each row has a linkbutton.

When i click that link button, i need to get the rows/cells information and make the information always visible on the screen .plz help

Posted 22-Sep-11 1:38am

Anjali Reddy

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Sunasara Imdadhusen 22-Sep-11 8:09am

You may create a DIV with always visible. whenever you clicked on link you need to set content of clicked row in DIV.

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Muralikrishna8811 · Answer 1 · 2011-09-22T05:35:00

Hi,

I tried some code for your requirement check this once

HTML

<html xmlns="http://www.w3.org/1999/xhtml">
<head runat="server">
    <title></title>
    <script src="Scripts/jquery-1.4.1-vsdoc.js" type="text/javascript"></script>
    <script src="Scripts/jquery-1.4.1.js" type="text/javascript"></script>
    <script language ="javascript" >
        function f1(tid) {
            document.getElementById("residv").innerHTML = tid;
            document.getElementById("residv").style.display = '';
            return false;
        }
 </script>
</head>
<body >
    <form id="form1" runat="server">
    <div>
        <asp:datalist id="DataList1" runat="server" xmlns:asp="#unknown">
            onitemcommand="DataList1_ItemCommand" 
            onitemdatabound="DataList1_ItemDataBound"  >
        <HeaderTemplate >  <table>
        </HeaderTemplate>
        <itemtemplate>
       
      
          <tr>
            <td>
              
            </td>
            <td>
                <asp:linkbutton id="LinkButton1" runat="server" commandname="save" commandargument="2">save</asp:linkbutton>
            </td>
          </tr>
        
        </itemtemplate>
        <footertemplate>
         </footertemplate></table>
        
        </asp:datalist>
        <div id="residv" style=" position:fixed; bottom :0px; right :0px; display :none; color:Red ;"></div>
    </div>
    </form>
</body>
</html>

And code behind file contains following code

C#

    protected void Page_Load(object sender, EventArgs e)
    {
        if (!IsPostBack)
        {
            List<string> g = new List<string>();
            g.Add("hjghj");
            g.Add("hjghj");
            g.Add("hjghj");
            g.Add("hjghj");
            g.Add("hjghj");
            g.Add("hjghj");
            g.Add("hjghj");
            DataList1.DataSource = g;
            DataList1.DataBind();
        }
    }


    protected void DataList1_ItemCommand(object source, DataListCommandEventArgs e)
    {
        if (e.CommandName == "save")
        {

        }
    }
    protected void DataList1_ItemDataBound(object sender, DataListItemEventArgs e)
    {
        if (e.Item.ItemType == ListItemType.Item || e.Item.ItemType == ListItemType.AlternatingItem)
        {
         
            LinkButton lblqid = (LinkButton)e.Item.FindControl("LinkButton1");
            string str="data retrieved from database "+e.Item.ItemIndex ;
            lblqid.OnClientClick = "return f1('"+str +"')";
        }
    }
</string></string>

In the above code you can retrieve data from database based on that item

If you use Jquery it is very simple than this

I hope you understood what I did,you get idea on what you can do for your requirement

All the Best.