OpenFileDialog
FileStream
img = new Bitmap(stream.ToString());
FileStream stream = new FileStream(Application.StartupPath + @"\TestData\img001-001.png", FileMode.Open); myImage.Image = Image.FromStream(stream); //display in pictureBox img = new Bitmap(stream.ToString());
var
This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)