count record and put into the field

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I have this table

ID         gender       companyName
1             M         Company A
2             M         Company A
3             F         Company A
4             F         Company B

I want this result:


CompanyName          M           MPercent    F     FPercent
Company A            2              66       1       33
Company B            0              0        1      100

*MPercent for Company A is 2/3 = 66%, FPercent is 1/3 = 33%.
*MPercent for Company B is 0/1 = 0%, FPercent is 1/1 = 100%.

Possible to get the result by using mysql query only?

Posted 27-Nov-12 22:03pm

melvintcs

Updated 27-Nov-12 22:04pm

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[no name] 28-Nov-12 4:05am

What have you tried ??

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DaleMoz · Accepted Answer · 2012-11-28T13:34:00

This will do it:

SQL

SELECT	[companyName],
	SUM(CASE WHEN gender='M' THEN 1 ELSE 0 END) AS M,
	(SUM(CASE WHEN gender='M' THEN 1 ELSE 0 END)*100)/COUNT(*) AS MPercent,
	SUM(CASE WHEN gender='F' THEN 1 ELSE 0 END) AS F,
	(SUM(CASE WHEN gender='F' THEN 1 ELSE 0 END)*100)/COUNT(*) AS MPercent
FROM	[tempdb].[dbo].[companyTable]
GROUP BY companyName

In response to your comment, you simply need to put a seperate query within the select clause:

SQL

SELECT  [companyName],
    SUM(CASE WHEN gender='M' THEN 1 ELSE 0 END) AS M,
    (SUM(CASE WHEN gender='M' THEN 1 ELSE 0 END)*100)/COUNT(*) AS MPercent,
    (SUM(CASE WHEN gender='M' THEN 1 ELSE 0 END)*100)/(SELECT COUNT(*) FROM companyTable) AS MTotalPercent,
    SUM(CASE WHEN gender='F' THEN 1 ELSE 0 END) AS F,
    (SUM(CASE WHEN gender='F' THEN 1 ELSE 0 END)*100)/COUNT(*) AS FPercent,
    (SUM(CASE WHEN gender='F' THEN 1 ELSE 0 END)*100)/(SELECT COUNT(*) FROM companyTable) AS FTotalPercent,
FROM    companyTable
GROUP BY companyName