Saranya,
Try this
if(FileUploader1.HasFile)
{
string filename = FileUploader1.PostedFile.FileName.ToString();
}
connectionstring();
SqlConnection con = new SqlConnection(str);
con.Open();
SqlCommand cmd = new SqlCommand("Excel", con);
cmd.CommandType = CommandType.StoredProcedure;
cmd.Parameters.Add("@ExcelName", SqlDbType.VarChar).Value = filename;
cmd.ExecuteNonQuery();
con.Close();
Thanks,
SP