How can I solve this without using arrays? I would appreciate anyone's help

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Write a program that keeps asking the user to enter the numbers between 0 and 999. Use a sentinel of your choice to stop taking numbers. What you need to do after getting all the numbers is to identify and display the most frequent digit that was entered. For example, if the user entered 3, 17, 81, 24, 354, 49, and 60, then the most frequent digit is 4.

Posted 27-Mar-10 13:29pm

7mesho

Updated 27-Mar-10 14:58pm

Luc Pattyn

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Luc Pattyn · Accepted Answer · 2010-03-27T18:10:00

there is a very simple hack that yields the results almost instantly, you don't even need to convert the user's input to numbers, all it takes is to concatenate all inputs in one huge string; then count the number of zeroes, ones, twos, etc. which can be done by checking string length change caused by replacing a digit by an empty string. The problem can be solved in 10 lines of code!

:)

rune711 · Accepted Answer · 2010-03-27T17:47:00

If you are sure you don't want to use arrays then you can try something like simply placing the numbers together in a string. You can then iterate through each character in the string and keep track of the count through a loop.

psudo code:

C#

private string allData;
public void GetData(string theNumber)
{
    allData += theNumber.ToString;
}
//after all the data is entered:
public string MostCounted()
{
    string currChar;
    int currCount;
    string highestCountedChar;
    int highestCharCount;
    for (int i = 0; i <= allData.Length - 1; i++) {
        currChar = allData.Substring(i, 1);
        for (int i = 0; i <= allData.Length - 1; i++) {
            if (currChar == allData.Substring(i, 1)) {
                currCount += 1;
            }
        }
        if (currCount > highestCharCount) {
            highestCountedChar = currChar;
            highestCharCount = currCount;
        }
        currCount = 0;
    }
    return highestCountedChar;
}

How can I solve this without using arrays? I would appreciate anyone's help

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