Result of Multiple Query in Single Row - SQL SERVER

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Hi,
I have table structure in Sql Server as below

SQL

Table - VisitorHits
VisitorId (int-IDENTITY(1,1)) (Primary Key)
VisitorDate (date) (Unique)
Hits (int) (default 0)

I have hits for different unique date in this table of my website, I have admin panel and I want to show following details
Total Visitors, Visitors This Month, Visitor Today

I want to make Select Query such that the data will be fetch as follow

SQL

TotalVisitor | VisitorThisMonth | VisitorToday
92373        | 46350            | 4045

How can I achieve this row using single query
I know that,
first result will be Sum of Hits in table
second result will be count of hits of rows where month is same as current
third result will be Hits of current day.

But I need all this thing in single row.
Please help me in generating query.
Thanks :)

Posted 13-Dec-13 21:30pm

amit Baswa

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2 solutions

Solution 2

visit here to understand concept..

http://www.comp.nus.edu.sg/~ooibc/courses/sql/dml_query_subquery.htm[^]

Posted 13-Dec-13 22:14pm

Rakesh Meel

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OriginalGriff · Accepted Answer · 2013-12-13T21:41:00

Solution 1

Try:

SQL

SELECT SUM(Hits) AS TotalVisitor,
       SUM(CASE WHEN DATEDIFF( m, VisitorDate, GETDATE() ) = 0 THEN 1 ELSE 0 END) AS VisitorThisMonth,
       SUM(CASE WHEN DATEDIFF( d, VisitorDate, GETDATE() ) = 0 THEN 1 ELSE 0 END) AS VisitorToday
FROM VisitorHits

Posted 13-Dec-13 21:41pm

OriginalGriff

Comments

amit Baswa 14-Dec-13 4:50am

Hi, Above query worked for me, but need some correction in above query as follow
SELECT
SUM(Hits) AS TotalVisitor,
SUM(CASE WHEN DATEDIFF( m, VisitorDate, GETDATE() ) = 0 THEN Hits ELSE 0 END) AS VisitorThisMonth,
SUM(CASE WHEN DATEDIFF( d, VisitorDate, GETDATE() ) = 0 THEN Hits ELSE 0 END) AS VisitorToday
FROM VisitorHits