how do this in jquery

Question

0.00/5 (No votes)

See more:

HTML

<head>
    <script type="text/javascript">
        $(document).ready(function () {
            $("#div1").hide(4000);
        });
        $(function () {
            $("#div1").slideDown(300);
        });
        $(document).ready(function () {
            $("#div2").hide(4000);
        });
        $(function () {
            $("#div2").slideDown(300);
        });
      
    </script>
</head>
<body>
    
    <div id="div1" style="background-color: red; width: 100px; height: 110px;"></div>
    <div id="div2" style="background-color: green; width: 110px; height: 120px;"></div>
</body>
</html>

i want to do slideDown frist for div1 and after complete this do SlideDown for div2!
i don't want take slideDown for both in one time!
how do that?

- MK Edit -
Codeblocks added.

Posted 9-Mar-14 10:20am

moosa il

Updated 9-Mar-14 12:18pm

Maarten Kools

v4

Add a Solution

2 solutions

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Sanket Saxena · Answer 1 · 2014-03-10T00:49:00

Solution 2

JavaScript

$(function () {
           $("#div1").slideDown(1000, function(){
           $("#div2").slideDown(1000)
        });

(Peter's solution will work)

Posted 10-Mar-14 0:49am

Sanket Saxena

Peter Leow · Answer 2 · 2014-03-09T15:01:00

Solution 1

You can put the slidedown method of div2 in a call back function of div1:

$(document).ready(function(){
            $("#div1, #div2").hide();
            $("#div1").slideDown(2000, function(){
                        $("#div2").slideDown(2000)
    });
})

Posted 9-Mar-14 15:01pm

Peter Leow

Updated 9-Mar-14 15:06pm

v4