SQL SERVER 'like' operator for datetime coloumn

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Hello!
How to use LIKE statement on a column of DateTime in MS SQL Server? I tried this code:

SQL

SELECT     custid, datetoday
FROM         customers
WHERE     (CONVERT(VARCHAR, datetoday, 101) LIKE '5/13/2014%')

but it gives me nothing :(

my dattetime column stores data like this: 5/13/2014 12:00:00 AM

Help please!

Posted 12-May-14 20:10pm

charliedev

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DamithSL 13-May-14 2:33am

you want to select records for today date?

charliedev 13-May-14 2:38am

Yes, I want to see the records for today only.

DamithSL 13-May-14 2:41am

check my answer below

Bernhard Hiller 13-May-14 2:40am

Is it necessary that you store the value as a DateTime instead of Date only? See http://technet.microsoft.com/en-us/library/bb630352%28v=sql.100%29.aspx

2 solutions

Solution 1

Depending on your objective, check these out:
1. sql-server-datetime-like-select[^]
2. sql-like-statement-on-a-datetime-type[^]

Posted 12-May-14 20:16pm

Peter Leow

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DamithSL · Accepted Answer · 2014-05-12T20:41:00

Solution 2

Quote:
I want to see the records for today only.

then try below

SQL

SELECT custid, datetoday
FROM customers
where  Cast(DATEDIFF(dd, datetoday, getDate()) as int) =0

Posted 12-May-14 20:41pm

DamithSL

Comments

charliedev 13-May-14 2:45am

This is perfect! Thanks so much :)

DamithSL 13-May-14 2:51am

You are welcome!

charliedev 13-May-14 3:10am

follow up question, what is the "dd" for in this line:
where Cast(DATEDIFF(dd, datetoday, getDate()) as int) =0

DamithSL 13-May-14 3:30am

check http://technet.microsoft.com/en-us/library/ms189794.aspx
dd for day