Please help everytime I try to run the program and pressed the register button it says "cannot open databse 'CCAD' requested by the login. login failed for user 'Jhocy-HP\Jhocy'. Please help

using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Windows.Forms;
using System.Data.SqlClient;

namespace register
{
    public partial class Reg : Form
    {
        public Reg()
        {
            InitializeComponent();
        }

        private void label4_Click(object sender, EventArgs e)
        {

        }

        private void textBox8_TextChanged(object sender, EventArgs e)
        {

        }

        private void button1_Click(object sender, EventArgs e)
        {
            try
            {

                SqlConnection con = new SqlConnection(@"Data Source=(localdb)\Projects;Initial Catalog=CCAD;Integrated Security=True");
                con.Open();

                SqlCommand cmd = new SqlCommand ("insert into [Admin](Username,Password,Firstname,Middlename,LastName,Gender,Birthday,Age,Email) values(@Username,@Password,@Firstname,@Middlename,@LastName,@Gender,@Birthday,@Age,@Email)", con);

                cmd.Parameters.AddWithValue("@Username", textBox1.Text);
                cmd.Parameters.AddWithValue("@Password", textBox2.Text);
                cmd.Parameters.AddWithValue("@Firstname", textBox3.Text);
                cmd.Parameters.AddWithValue("@Middlename", textBox4.Text);
                cmd.Parameters.AddWithValue("@LastName", textBox5.Text);
                cmd.Parameters.AddWithValue("@Gender", textBox6.Text);
                cmd.Parameters.AddWithValue("@Birthday", textBox7.Text);
                cmd.Parameters.AddWithValue("@Age", textBox8.Text);
                cmd.Parameters.AddWithValue("@Email", textBox9.Text);
                cmd.ExecuteNonQuery();
                con.Close();

                MessageBox.Show("Register Complete!", "Massage", MessageBoxButtons.OK, MessageBoxIcon.Information);


            }
            catch (Exception ex)
            {
                MessageBox.Show(ex.Message, "error", MessageBoxButtons.OK, MessageBoxIcon.Error);
            }
            finally
            {

            }
        }

        private void button2_Click(object sender, EventArgs e)
        {
            Login form = new Login();
            this.Hide();
            form.Show();
        }
    }
}