Show pages based on dataGridView1_CellContentClick using if-stetement

Question

0.00/5 (No votes)

See more:

Hi all

my code is :

C#

private void dataGridView1_CellContentClick(object sender,DataGridViewCellEventArgs e)
      {
          Setting_forms fis = new Setting_forms();

          if (e.ColumnIndex == 8)
          {
              fis.Check_codem = dataGridView1.Rows[dataGridView1.CurrentRow.Index].Cells["code_m_Grid"].Value.ToString();
          }
          string us_geid = dataGridView1.Rows[dataGridView1.CurrentRow.Index].Cells["type_zemanat_grid"].Value.ToString();

          if (us_geid == "chek")
          {
              new Show_sub_check().ShowDialog();
          }
          if (us_geid == "safteh")
          {
              new Shosw_sub_safteh().ShowDialog();
          }
          if (us_geid == "tala")
          {
              new Show_sub_tala().ShowDialog();
          }
      }

"e.ColumnIndex == 8 " is linkedlabel in datagridview , when click on that
my form in if-statement is showed , but the last of form in if-statement don't showed.

Posted 23-Feb-15 8:01am

bernova

Updated 23-Feb-15 17:43pm

Sujith Karivelil

v4

Add a Solution

1 solution

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

OriginalGriff · Answer 1 · 2015-02-23T08:14:00

If you mean that the first two if conditions show a dialog and the third one doesn't, then we can't really help you here: we don;t have access to the rest of your code, so we can't run it.

So start with the debugger: put a breakpoint on the first line in the event handler, and run your app. When it hits the breakpoint, your app will stop, and you can use the debugger to examine exactly what is going on. Hover your mouse over a variable, and it will show the value; you can also single step each instruction to see exactly what is happening where and why.

When you know exactly where the execution is going, you should be able to work it out, but if you can't at least you will be able to tell us! :laugh:
If may be as simple as "string comparisons are case sensitive" so "tala" and "Tala" are not the same, or that "tala" is different to "tala ".
But we can't tell from here!