Rvalue
s and
lvalue
s are a fundamental concept of
C++ programming. In essence, an
rvalue
is an expression that cannot appear on the left-hand side of an assignment expression. By contrast, an
lvalue
refers to an object (in its wider sense), or a chunk of memory, to which you can write a value. References can be bound to both
rvalue
s and
lvalue
s. However, due to the language’s restrictions regarding
rvalue
s, you have to be aware of the restrictions on binding references to
rvalue
s, too.
Binding a reference to an
rvalue
is allowed as long as the reference is bound to a
const
type. The rationale behind this rule is straightforward: you can’t change an
rvalue
, and only a reference to
const
ensures that the program doesn’t modify an
rvalue
through its reference. In the following example, the function
f()
takes a reference to
const int
:
void f(const int & i);
int main()
{
f(2);
}
The program passes the
rvalue 2
as an argument to
f()
. At runtime,
C++ creates a temporary object of type
int
with the value
2
and binds it to the reference
i
. The temporary and its reference exist from the moment
f()
is invoked until it returns; they are destroyed immediately afterwards. Note that had we declared the reference
i
without the
const
qualifier, the function
f()
could have modified its argument, thereby causing undefined behavior. For this reason, you may only bind references to
const
objects.
The same rule applies to user-defined objects. You may bind a reference to a temporary object only if it’s
const
:
struct A{};
void f(const A& a);
int main()
{
f(A());
}