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Chris Maunder wrote: - One. He gives it to four programmers, thereby simplifying the problem to a previous question.
Forgot to quote that one...
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So this is why you created a maths forum
Ryan "Punctuality is only a virtue for those who aren't smart enough to think of good excuses for being late" John Nichol "Point Of Impact"
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Chris Maunder wrote: tell me how the trees helped?"
"Certainly", say the snakes. "We're adders, so we need logs to multiply
I'd like to help but I am too lazy to Google it for you.
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What's the difference between an introverted and an extroverted mathematician?
Well, the extroverted looks, while talking, on YOUR shoes!
If you let choose a mathematician between a bread roll and eternal blissfulness, what does he take?
The bread roll of course! Nothing is better than eternal blissfulness - and a bread roll is better than nothing.
A man has married a female mathematician. He comes home, gives her bunch of roses and says "I love you!"
She takes the roses, throws them on the floor and kicks him out of their residence. What has he done wrong?
He should had said: "I love you, and only you!"
How many mathematicians do you need to change a light bulb?
- Just one, but 400 apply for the job
Regards,
Ingo
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mexican jokes on a maths board?!
--
Not based on the Novel by James Fenimore Cooper
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We've already outsourced all the tedious manual labor, so now it's time to give up arithmetic...
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You want that in imperial or decimal?
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Ok lets me be the first to ask a maths question
Find a number which
1. divided by 10 gives a remainder 9
2. divided by 9 gives remainder 8
---
---
so on till
divided by 2 gives a remainder 1
Any one ?
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It's not a mexican is it ?
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Here's a wild guess:
123456789 ? [edit] ok I got the 9 bit :p [edit]
-- modified at 18:37 Wednesday 26th July, 2006
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2701439
last 4 digits by deduction, rest trial and error guess with 3/9 rule.
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Provided I've understood the question correctly, I think I've solved it. I kind of cheated though; I wrote a C# program that solves this:
int start = 1;
int divisor = 10;
while (divisor >= 2)
{
if (start % divisor == divisor - 1)
{
divisor--;
}
else
{
start++;
divisor = 10;
}
}
Soon as that loop exits, you've got your number, which happens to be 2519.
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Judah Himango wrote: I kind of cheated.
He did say "find a number"
So there are more than one of these. I wonder if its some kind of series...
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There was a question of if there were more number, yes, there are. Here is a modification of your code that shows others
#include <iostream>
using namespace std;
int main()
{
int start = 1;
int divisor = 10;
while ( start <1000000 )
{
while (divisor >= 2)
{
if (start % divisor == divisor - 1)
{
divisor--;
}
else
{
start++;
divisor = 10;
}
}
cout<<start<<endl;
divisor=10;
start++;
}
return 0;
}
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yes thats true
there are many , but if you think it might take a day to get the solution , without any computer help, but its worth
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Judah Himango wrote: It appears to be every 2520.
It is. Modifying the your code that I modified and posted, shows this to be true
I'd like to help but I am too lazy to Google it for you.
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leppie wrote: So there are more than one of these. I wonder if its some kind of series...
Take a look at the modification of Judah's code that I posted. Your number is one of the numbers that come up
I'd like to help but I am too lazy to Google it for you.
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Judah Himango wrote: I kind of cheated though
well thats ok , and of course there are more numbers
but the fun is when you deduce how to do it
It's the journey, not the destination
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Quartz... wrote: It's the journey, not the destination
Very true. I actually had fun writing a little piece of code to solve it, though, so it was the journey even still. I added some more code that added each match to a list box on a Windows Form. Then, after seeing how it froze up the UI, I did it on a background thread. Still, the UI thread would get flooded with matches, almost preventing it from painting, so I further chagned the code to only update during app idle. Voila, cool little WinForms program that solves it.
Tech, life, family, faith: Give me a visit.
I'm currently blogging about: Messianic Instrumentals (with audio)
The apostle Paul, modernly speaking: Epistles of Paul
Judah Himango
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Judah Himango wrote: Voila, cool little WinForms program that solves it.
That's cool. Mine is just a plain boring console app :->
I'd like to help but I am too lazy to Google it for you.
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N(1) = 2519
N(2) = 2519 + 2520 = 5039
N(3) = 2519 + 2520 + 2520 = 7559
N(4) = 2519 + 2520 + 2520 + 2520 = 10079
...
N(n) = 2519 + (n - 1)*(2520)
No idea what the heck it means, though. Care to enlighten us mathematically-challenged folks?
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