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The ComboBox doesn't expose a double-click event. Frankly, it's not inuitive to double-click on anything in a ComboBox, so why would you need it?
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Thanks for replying..
My situation goes this way... my combobox holds the list of my contacts.. and if i want to view / edit Personal Information of that specific contact.. i'll just double click the combo box to show my contacts information form... In that way i can go to my contacts info by just double clicking my combox...
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Hi!,
I am not trying to ask you to change the design of your app., but a feasible solution is an Edit button right besides the cboBox so that the user may select the comboBox item and then click on edit to edit the selected record.
This way the user is not forced to do any extra thing, since any which way he had to click TWICE to edit/view the record.
Hope this helps you out in some way or the other.
Happy Programming!!!!
Vaibhav Sharma...
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Your right, but the company stantard is use to that.. hehehe... I just adapt it to my next project.. thank for sharing...
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Make it any way you wish. The ComboBox still doesn't expose a double-click event.
ListBox and ListView, more traditionally used for what you describe, both expose a double-click.
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Hi All,
In VB6's, Combobox has MatchWithList...
My problem is, i cant find the counterpart or equivalent of MatchWithList in VB 2005's Combo Box..
Does anybody knows where can i find it?
Please help and thanks in advance....
Widgets....
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You're looking for the AutoCompleteMode and AutoCompleteSource properties.
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Thanks alot is working...
Is there any property that will let me know if that AutoCompleteSource will nothing so suggest..? something like giving "true" if it suggested a string or "false" if it no suggested string?
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Nope. You'd have to make your own version of the ComboBox to do that. Probably tracking how many characters the user actually typed against the length of the string in the Text property, maybe.
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public static bool MatchWithList(ref ComboBox cmb, string cmbText)
{
bool matchexists = false;
int i = cmb.FindStringExact(cmbText);
if (i != -1)
{
cmb.SelectedIndex = i;
matchexists = true;
}
else
{
matchexists = false;
}
return matchexists;
}
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Yeah....ok. And why are you replying to a 4 year old message??
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Is it possible to sort a record in crystal report using Formula Fields? Example: I want to sort my List of Depositors base on there Balance... Wherein Balance = Sum({Deposit} - Sum{Withdrawal}... ?
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Create a new Group based on the formula.
Tom Garth
Developer
R. L. Nelson and Associates, Inc., Virginia
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Does any one know how to create a drop-down menu on a LinkLabel?
I want to create a LinkLabel called 'Language', once a user clicks on 'Language' further links will show i.e France, English, Spain ect. The user then select the language type.
Ian Wells
irwells@hotmail.com
I'm useing Visual Studio.net 2005 - Visual Basic
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Hi Ian,
Assuming that you are talking about a windows form and not a web page, the answer is: you can't. The LinkLabel is simply not the correct control for this.
However, despair not. There are ways (from easy to difficult):
1. Instead use the ComboBox control which is pretty much the windows forms version of the drop down menu as found on web pages. (the pragmatic solution)
2. create a little form and populate it with buttons or labels or something, with the language alternatives you want. Make it look the way you want and make it appear right under your LinkLabel when you click it. (i.e. fake it)
3. Make a custom control that looks and acts the way you want. Best would probably be again to inherit the ComboBox control, and change its appearance. This solution is basically the same as number 1. except that it is a lot more work. (the stubborn solution)
Good luck with it,
Johan
My advice is free, and you may get what you paid for.
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Hi Johan,
I've taken your advice and created a combobox instead.
Many Thanks
Ian
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Hi.
I have this code:
for i as integer=0 to array.lenght-1 <br />
if array(i)=value1 then<br />
var=true<br />
end if<br />
if var=true then<br />
....<br />
next
I need to set the value1 on the first position of the array and the first position of the array must be set on the last position of the array.
I don't have any idea.
thanks
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WhiteGirl23 wrote: I need to set the value1 on the first position of the array and the first position of the array must be set on the last position of the array.
In that order? If you do it in that order then value1 will be set on the first and last positions of the array.
Try this:
array(array.Length - 1) = array(0)
array(0) = value1
-- Always write code as if the maintenance programmer were an axe murderer who knows where you live.
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no.isn't good.
I want to keep all the values of the array.
In array(array.length-1)=must keep the first position of the vector before I make array(0)=value1.
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Please always paste the actual code, in case a typo changes the context of something.
How do you mean ? You want to swap the first and last items ?
Christian Graus - Microsoft MVP - C++
"I am working on a project that will convert a FORTRAN code to corresponding C++ code.I am not aware of FORTRAN syntax" ( spotted in the C++/CLI forum )
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example: I have a string :123#123.123#(local)
I split this string:
array()=string.split("#")
I'm looking for a value on this array.I take (local)
I found the position of this value:array((2).
I want to move array(2) on the first position of the array,but I don't want to loose elements of the array,and the last position of the array must be=123.
Something like this:
string=(local)#123.123#12 3
Thanks.
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So you want to *swap* the elements.
So you do this:
dim o as object = array(0)
array(0) = array(array.Length = 1)
array(array.Length - 1) = o
Christian Graus - Microsoft MVP - C++
"I am working on a project that will convert a FORTRAN code to corresponding C++ code.I am not aware of FORTRAN syntax" ( spotted in the C++/CLI forum )
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Hai
I have inherited datagridview control as custom control and added one textbox control on it. I have added some code in textbox keypress(or keyup,keydown).
The problem is
When i press enter key the event doesn't raises but other keys works.
what is the broblem here? pls explain
Thanks
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