Visual Basic

Re: Double Click on Combo Box

26-Aug-07 16:45

Your right, but the company stantard is use to that.. hehehe... I just adapt it to my next project.. thank for sharing...

Dave Kreskowiak26-Aug-07 15:48

Re: Double Click on Combo Box

26-Aug-07 15:48

Make it any way you wish. The ComboBox still doesn't expose a double-click event.

ListBox and ListView, more traditionally used for what you describe, both expose a double-click.

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Dave Kreskowiak
Microsoft MVP
Visual Developer - Visual Basic
2006, 2007

Widgets26-Aug-07 20:10

MatchWithList in Combo Box?

26-Aug-07 20:10

Yap, thanks dave...

Widgets25-Aug-07 23:47

25-Aug-07 23:47

Hi All,

In VB6's, Combobox has MatchWithList...

My problem is, i cant find the counterpart or equivalent of MatchWithList in VB 2005's Combo Box..

Does anybody knows where can i find it?

Please help and thanks in advance....

Widgets....

Dave Kreskowiak26-Aug-07 4:25

26-Aug-07 4:25

You're looking for the AutoCompleteMode and AutoCompleteSource properties.

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Dave Kreskowiak
Microsoft MVP
Visual Developer - Visual Basic
2006, 2007

Widgets26-Aug-07 15:29

26-Aug-07 15:29

Thanks alot is working...

Is there any property that will let me know if that AutoCompleteSource will nothing so suggest..? something like giving "true" if it suggested a string or "false" if it no suggested string?

Dave Kreskowiak26-Aug-07 15:43

26-Aug-07 15:43

Nope. You'd have to make your own version of the ComboBox to do that. Probably tracking how many characters the user actually typed against the length of the string in the Text property, maybe.

A guide to posting questions on CodeProject[^]

Dave Kreskowiak
Microsoft MVP
Visual Developer - Visual Basic
2006, 2007

Suraj Babu19-Aug-11 0:10

Suraj Babu

19-Aug-11 0:10

///Please use this function for MatchWithList
public static bool MatchWithList(ref ComboBox cmb, string cmbText)
{
    bool matchexists = false;

    int i = cmb.FindStringExact(cmbText);
    if (i != -1)
    {
        cmb.SelectedIndex = i;
        matchexists = true;
    }
    else
    {
        matchexists = false;
    }

    return matchexists;
}

Dave Kreskowiak19-Aug-11 1:57

Sorting Report using Formula Fields?

19-Aug-11 1:57

Yeah....ok. Unsure | :~

And why are you replying to a 4 year old message??

A guide to posting questions on CodeProject[^]

Dave Kreskowiak

Widgets25-Aug-07 23:46

Re: Sorting Report using Formula Fields?

25-Aug-07 23:46

Is it possible to sort a record in crystal report using Formula Fields? Example: I want to sort my List of Depositors base on there Balance... Wherein Balance = Sum({Deposit} - Sum{Withdrawal}... ?

TomGarth27-Aug-07 6:09

TomGarth

27-Aug-07 6:09

Create a new Group based on the formula.

Tom Garth
Developer
R. L. Nelson and Associates, Inc., Virginia

LinkLabel dropdown menu

Ian Wells25-Aug-07 9:43

Ian Wells

25-Aug-07 9:43

Does any one know how to create a drop-down menu on a LinkLabel?

I want to create a LinkLabel called 'Language', once a user clicks on 'Language' further links will show i.e France, English, Spain ect. The user then select the language type.

Ian Wells
irwells@hotmail.com

I'm useing Visual Studio.net 2005 - Visual Basic

Re: LinkLabel dropdown menu

Johan Hakkesteegt31-Aug-07 2:25

Johan Hakkesteegt

31-Aug-07 2:25

Hi Ian,

Assuming that you are talking about a windows form and not a web page, the answer is: you can't. The LinkLabel is simply not the correct control for this.
However, despair not. There are ways (from easy to difficult):
1. Instead use the ComboBox control which is pretty much the windows forms version of the drop down menu as found on web pages. (the pragmatic solution)
2. create a little form and populate it with buttons or labels or something, with the language alternatives you want. Make it look the way you want and make it appear right under your LinkLabel when you click it. (i.e. fake it)
3. Make a custom control that looks and acts the way you want. Best would probably be again to inherit the ComboBox control, and change its appearance. This solution is basically the same as number 1. except that it is a lot more work. (the stubborn solution)

Good luck with it,

Johan

My advice is free, and you may get what you paid for.

Re: LinkLabel dropdown menu

Ian Wells9-Sep-07 2:31

Ian Wells

9-Sep-07 2:31

Hi Johan,

I've taken your advice and created a combobox instead. Smile | :)

Many Thanks

Ian

array

WhiteGirl2325-Aug-07 7:36

25-Aug-07 7:36

Hi.
I have this code:

for i as integer=0 to array.lenght-1 <br />
if array(i)=value1 then<br />
var=true<br />
end if<br />
if var=true then<br />
....<br />
next

I need to set the value1 on the first position of the array and the first position of the array must be set on the last position of the array.
I don't have any idea.
thanks

Colin Angus Mackay25-Aug-07 12:09

Colin Angus Mackay

25-Aug-07 12:09

WhiteGirl23 wrote:
I need to set the value1 on the first position of the array and the first position of the array must be set on the last position of the array.

In that order? If you do it in that order then value1 will be set on the first and last positions of the array.

Try this:

array(array.Length - 1) = array(0)
array(0) = value1

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WhiteGirl2325-Aug-07 19:30

25-Aug-07 19:30

no.isn't good.
I want to keep all the values of the array.
In array(array.length-1)=must keep the first position of the vector before I make array(0)=value1.

Christian Graus25-Aug-07 20:20

Christian Graus

25-Aug-07 20:20

Please always paste the actual code, in case a typo changes the context of something.

How do you mean ? You want to swap the first and last items ?

Christian Graus - Microsoft MVP - C++

"I am working on a project that will convert a FORTRAN code to corresponding C++ code.I am not aware of FORTRAN syntax" ( spotted in the C++/CLI forum )

WhiteGirl2325-Aug-07 20:32

25-Aug-07 20:32

example: I have a string :123#123.123#(local)
I split this string:
array()=string.split("#")
I'm looking for a value on this array.I take (local)
I found the position of this value:array((2).
I want to move array(2) on the first position of the array,but I don't want to loose elements of the array,and the last position of the array must be=123.
Something like this:
string=(local)#123.123#123
Thanks.

Christian Graus25-Aug-07 20:35

Christian Graus

25-Aug-07 20:35

So you want to *swap* the elements.

So you do this:

dim o as object = array(0)
array(0) = array(array.Length = 1)
array(array.Length - 1) = o

Christian Graus - Microsoft MVP - C++

"I am working on a project that will convert a FORTRAN code to corresponding C++ code.I am not aware of FORTRAN syntax" ( spotted in the C++/CLI forum )

WhiteGirl2326-Aug-07 4:02