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If you have any difficulties with this implementation (lots of action class need to be change) let me know there are other types of implementation available.
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Hi folks
I need a java program which can able to read and write smart card data.
how to do this??
I did not get any accurate programs through which I can able to get this functionality.
Valuable suggestions highly welcome.
$ai
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I'm a beginner in Java, learning on my own. And I want to test my knowledge in multiple classes and method with parameters.
Can you suggest any simple machine problem?
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Look at the Java Tutorials[^] where you will find lots of samples that you can easily modify.
Use the best guess
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Do you want a practice with class inheritance?
If yes: create a command line chess set, no AI need, just recreate the basic methods of movements,etc.
no: create a command line turtle graphics app. Here is a turtle graphics problem definition:
http://www.bfoit.org/itp/IntroCmdsScreencast.html[^]
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Hi..
I am using eclipse juno,tomcat6.
I want to read the property file only by name. and path should be my current location.
currenttly i have hard coded the path. "E:\SERENE0121201311\phibro\param.properties". But when i read the current path it shows "E:\Eclipse_Juno" but it should be ""E:\SERENE0121201311\phibro".
Can anyone help me to set application path..
Thanks
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How are you obtaining the current path and why do think it is wrong?
Use the best guess
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File file = new File(".");
System.out.println("Current dir : " + file.getCanonicalPath());
I am using above code to get current path...
this gives output : E:\Eclipse_Juno
but my code is inside : E:\SERENE0121201311\phibro
I need above path?
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It doesn't matter where your code is it is where you start the program from that is the current directory.
Use the best guess
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I have tried many options but could not get.
please let me know what is the best?
Thanks in advance.
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I am using below code and their output in comment (//)
I need this path "E:\SERENE0121201311\phibro" i have code inside this path...
try{
File file = new File(".");
System.out.println("Path 1 : " + file.getCanonicalPath());\
//E:\Eclipse_Juno
System.out.println("Path 2 : " +new java.io.File("").getAbsolutePath());
//E:\Eclipse_Juno
System.out.println("Path 2 : " + file.getCanonicalFile());
//E:\Eclipse_Juno
String path = getClass().getProtectionDomain().getCodeSource().getLocation().getPath();
System.out.println("Path 4 : " + this.getClass().getClassLoader().getResource("").getPath());
///E:/SERENE0121201311/.metadata/.plugins/org.eclipse.wst.server.core/tmp1/wtpwebapps/phibro/WEB-INF/classes/
String s = currentRelativePath.toAbsolutePath().toString();
//E:\Eclipse_Juno
String myCurrentDir = System.getProperty("user.dir")
+ File.separator
+ System.getProperty("sun.java.command")
.substring(0, System.getProperty("sun.java.command").lastIndexOf("."))
.replace(".", File.separator);
System.out.println("Path 5 : " +myCurrentDir);
//E:\Eclipse_Juno\org\apache\catalina\startup
Path currentRelativePath = Paths.get("");
System.out.println("path 6 : "+path);
///E:/SERENE0121201311/.metadata/.plugins/org.eclipse.wst.server.core/tmp1/wtpwebapps/phibro/WEB-INF/classes/com/crmod/job/impl/XmlRead.class
}catch(Exception e){
e.printStackTrace();
}
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If you know the path that you want then you will need to code it into your program. It is obvious that when you execute your program you are not starting in that directory, so none of the other methods will give you the path that you want.
Use the best guess
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I need to deploy my web site to somewhere else so must know the path of phibro(my website folder name) folder. if i do hard code then it will create problem.. so please let me know if any other way to do it..
Thanks
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I am not familiar with java web sites, but I would assume that there is some property in Tomcat that will give you the correct location.
Use the best guess
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I want simple example code in web service then related websites for studies.
By
R.Ganesh Babu
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If you type that into a google search, you will find all kinds of example code and references.
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Ok, But I want, if you know best websites, you send to me.
Thanks & Regards,
R.Ganesh Babu
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What have you tried and where are you stuck? "in java" is not much of a description of a problem....
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I used JPanel leftPanel = new JPanel(new GridBagLayout); to contain "JScrollPane, JRadioButton, JCheckBox" (Like this image).
When I click on "Open..." button to add more picture, the JScrollPane will use "m_arrListImageFilePaths" to auto update its items. Controls in "JLeftPane" is still right their position. But when I click on application's "Maximum" button - the controls is repainted, "Normal" button is lay down "JScrollPane" (Like this video). Please help me solve above problem.
By the way, I attached my project which is helpful in your solving.
Thanks all !!!!!
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How to create last 10 recently opened files list using java in netbeans?
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Try some of these links[^]. Basically, it looks like you have to write the code yourself.
Use the best guess
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i want my program run in swing gui and yield can displayed in jtable.
Everybody,plese help me.
import java.io.*;
public class wile {
public static void main(String[]args){
BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
String cthdata=("Contoh Data");
String nomber=null;
try{
System.out.print("masukan jumlah:");
nomber=br.readLine();
}
catch(IOException ioe){
System.out.println("gagal");
}
int intnumber;
intnumber=Integer.parseInt(nomber);
System.out.println("No\tIsi");
int no=1;
while(no<=intnumber){
System.out.println(no+"\t"+cthdata);
no=no+1;
}
}
}
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